Material implication: is p→q ⊨ ¬p∨q valid?
p → q holds in exactly the rows where ¬p ∨ q holds: either the antecedent fails, or the consequent holds. A conditional is a disjunction in disguise.
Valid
p→q ⊨ ¬p∨qEvery branch of the tableau closes, so nothing makes the premises true and the conclusion false at once.
Proof (semantic tableau)
- 1True: p→qpremise
- 2False: ¬p∨qnegated conclusion
- 3False: ¬pfrom line 2
- 4False: qfrom line 2
- 5True: pfrom line 3
- 6False: pfrom line 1
Branch closed: line 6 contradicts line 5.
- 7True: qfrom line 1
Branch closed: line 7 contradicts line 4.
closed branch